Proof : PA x PB = PT^2 | Tangents to a circle |Geometry Class X

In this video we prove the statement for PA x PB = PT^2 or in other words,
Proof: If from an external point P of a circle a tangent segment PT and a secant PAB are drawn, then PA.PB=PT^2

Khan Academy is a free learning platform for Class 1-12 students with videos, exercises, and tests for maths, science, and more subjects. Our content is aligned to CBSE syllabus and available in Hindi, English, and many more regional languages.


Experience the joy of easy, seamless, accessible learning anywhere, anytime with Khan Academy.


Subscribe to our YouTube channel - https://www.youtube.com/c/khanacademy

As a 501(c)(3) nonprofit organization, we would love your help!
Donate here: https://www.khanacademy.org/donate?utm_source=youtube&utm_medium=desc

Created by Devashish Phadnis