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sinx = sin(π-x) cosx= -cos(π-x) sinx=-sin(2π-x) tanx=tan(π+x)
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5 ビュー·
06 行進 2024
A quick little video to explain question 332 #17 in the Nelson Advanced Functions textbook which deals with equivalent trig expressions.
sinx = sin(π-x) cosx= -cos(π-x)
sinx=-sin(2π-x) tanx=tan(π+x)
もっと見せる
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